Lakers' Dwight Howard to signal 1-year deal with 76ers
Nov. 20 (UPI) -- Historical Los Angeles Lakers center Dwight Howard is signing a short lived contract with the Philadelphia 76ers.
League sources told ESPN and The Athletic on Friday that Howard's one-year deal is for the weak minimal of $2.6 million.
Howard's settlement with the 76ers became reported quickly after the eight-time All-Well-known person selection indicated on social media that he became re-signing with the Lakers. In the since-deleted tweet, the three-time NBA Defensive Participant of the one year stated he became "staying upright where I belong."
"I'm staying upright where I belong. Laker Nation I cherish y'all. Crimson and gold by no system will get broken-down," Howard wrote on Twitter.
Howard signed a one-year, $2.56 million contract with the Lakers in August 2019. He came off the bench in all but two of his 69 video games this previous season, averaging 7.5 functions, 7.3 rebounds and 1.1 blocks per sport.
The 34-year-broken-down Howard played even fewer minutes within the playoffs, but he managed to take hang of his first NBA championship in his 16th season.
Howard, who's even handed one of many supreme substantial males of his period, has averaged 16.7 functions, 12.3 rebounds and 1.9 blocks per sport in his NBA profession. He has played for the Orlando Magic, Houston Rockets, Charlotte Hornets, Washington Wizards and Lakers.